In a common emitter amplifier, using output reisistance of `5000` ohm and input resistance fo `2000`ohm, if the peak value of input signal voltage is `10 m V` and `beta=50`, then the peak value of output voltage is

Options

A. 1.25 V
B. 12.5 V
C. 125V
D. 1250 V

Answer

A

Explanation

`R_(0)=5000 Omega , R_(i)=2000, V_(i)=10 mV, beta=50, V_(0)=?`
`A_(v)=(V_(0))/(V_(i))=beta*(R_(0))/(R_(i))`
`V_(0)=betaV_(i)(R_(0))/(R_(i))`
`=50xx10xx10^(-3)xx(5000)/(2000)`
`=50xx10xx2.5xx10^(-3)`
`=1250xx10^(-3)V`
`=1.25 V`