Home
Class 12
PHYSICS
In a common base transistor amplifier if...

In a common base transistor amplifier if the input resistance `R_(i)` is 200 `Omega` and load resistance `R_(L)` is `20K Omega` , find voltage gain `(alpha=0.95)`

A

86

B

98

C

95

D

190

Text Solution

Verified by Experts

The correct Answer is:
C

`R_(i)=200 Omega, R_(0)=20 K Omega, A_(v)= ? Alpha=0.95`
Now `A_(v)=alpha(R_(0))/(R_(i))`
`=0.95xx(2000)/(200)=0.95xx200=190`
Promotional Banner

Topper's Solved these Questions

  • ROTATIONAL MOTION

    NIKITA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS|405 Videos
  • STATIONARY WAVES

    NIKITA PUBLICATION|Exercise MCQs|396 Videos

Similar Questions

Explore conceptually related problems

For a common emitter amplifier, input resistance (R_i) = 500Omega and load resistance R_L = 5000Omega . If beta = 60, then the voltage gain is

In a common emitter amplifier , the input resistance is 200 Omega and load resistance is 40 K Omega . If the current gain is 80, the voltage gasin of the amplifier is

In a common emitter amplifier , the input resistance is 1 Omega and load resistance is 10 K Omega . If the current gain is 100, the voltage gasin of the amplifier is

In common emitter transistor, the input resistance is 200Omega and bad resistance is 40kOmega . If current gain is 80 then voltage gain is

For a transistor, beta = 50. Input resistance ( R_i ) = 200 Omega . Output resistance ( R_o ) = 2000 Omega . The voltage gain of the amplifier is

What is the voltage gain in a common emitter amplifier when the input resistance is 200 Omega and the load resistance is 1 K Omega ? ( beta = 50 )

A common emitter transistor amplifier has a current gain of 50 . If the load resistance is 4k Omega , and input resistance is 500 Omega , the voltage gain of amplifier is.

What is the voltage gain in a common emitter amplifier where input resistance is 3 Omega and load resistance is 24 Omega :- (beta = 6) ?

NIKITA PUBLICATION-SEMICONDUCTORS-MCQS
  1. In CE configuration of a transistor, input resistance is 2 K Omega...

    Text Solution

    |

  2. In a common emitter amplifier, using output reisistance of 5000 ohm an...

    Text Solution

    |

  3. In a common base transistor amplifier if the input resistance R(i) is ...

    Text Solution

    |

  4. The major constituent of transistor are

    Text Solution

    |

  5. If the current gain is 100, then the emitter current in a transistor f...

    Text Solution

    |

  6. Rectification is the process for the conversion of

    Text Solution

    |

  7. Why is the semiconductor damaged by a strong current?

    Text Solution

    |

  8. In the working of n-p transistor, the number of free electrons which r...

    Text Solution

    |

  9. The carriers in base region of a p-n-p transistor are

    Text Solution

    |

  10. What is the process of introduction of impurity in semiconductor ?

    Text Solution

    |

  11. In a p-n junction , numbers of junction are

    Text Solution

    |

  12. Bond in n and p-type semiconductor is

    Text Solution

    |

  13. in common emitter amplifier, the emitter base junction is

    Text Solution

    |

  14. p-type semicondutor and n-type semicondutor are formed by

    Text Solution

    |

  15. Freuency of given AC signal is 50 Hz. When it connected to a half - wa...

    Text Solution

    |

  16. What is amount of doping tansistor ?

    Text Solution

    |

  17. To obtain n-type semiconductor , the impurity introduced is

    Text Solution

    |

  18. Emitter base and collector base junction in n-p-n transistor are

    Text Solution

    |

  19. Rectifier is used to

    Text Solution

    |

  20. How many electrodes are there in a transistor ?

    Text Solution

    |