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In common base circuit of a transistor ,...

In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mA

A

2 mA

B

4 mA

C

6 mA

D

8 mA

Text Solution

Verified by Experts

The correct Answer is:
B
Given , `alpha=0.95, I_(e)=? , I_(b)=0.2 mA`
`alpha=(I_(c))/(I_(e))=(I_(e)-I_(b))/(I_(e))`
`alpha I_(e)=I_(e)-I_(b)`
`I_(b)=I_(e)(1-alpha)`
`I_(e)=(I_(b))/(I-alpha)`
`=(0.2)/(1-0.95)=(0.2)/(0.05)=4 mA`
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