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The path length of oscillation of simple...

The path length of oscillation of simple pendulum of length 1 m is 16 cm. Its maximum velocity is (take, `g=pi^(2)m//s^(2)`)

A

`2 pi cm//s`

B

`4 picm//s`

C

`8 pi cm//s`

D

`16 pi cm//s`

Text Solution

Verified by Experts

The correct Answer is:
C
Data:
Path length `(2a) =16 cm`
` a=8 cm`
`T=2pi sqrt((1)/(g))- 2pisqrt((1)/(pi_(2)))=2pixx1/pi=2s`
`Vm =a omega`
`=axx (2pi)/(T)= 8 xx(2pi)/(2)`
`=8 pi cm//s.`
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Knowledge Check

  • IF the length of a simple pendulum is increased, its maximum velocity during oscillation

    A
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    B
    increases
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  • A simple pendulum 50cm long is suspended from the roof of a acceleration in the horizontal direction with constant acceleration sqrt(3) g m//s^(-1) . The period of small oscillations of the pendulum about its equilibrium position is (g = pi^(2) m//s^(2)) ltbRgt

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    C
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  • A graph is drawn between the displacement and time taken for the oscillations of a simple pendulum. The length of the pendulum is _______ m (if g=10ms^(-2)andpi^(2)=10 )

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