An alternating voltage `E=200sqrt(2)sin(100t)` is connected to a `1` microfarad capacitor through an AC ammeter. The reading of the ammeter shall be

Options

A. `5mA`
B. `10mA`
C. `15mA`
D. `20mA`

Answer

D

Explanation

Sata
`e=200 sqrt2 sin (100t )` volt
`C =1 mu F`
`I_(rms)?`
`to X _(C) =(1)/(w_(C))=(1)/(100xx10^(-6))=10^(4)`
Now
`I_(0) =(e_(0))/(X_(c))% I_(rms) =(I_(0))/(sqrt2) `
`thereforeI _(rms) =(200sqrt2)/(sqrt 2 xx10^(4))=200xx10^(-4) A`
`=20xx10^(-3) A = 20mA`