If numerical aperture of a microscope is increased, then its

Options

A. resolving power remains constant
B. resolving power becomes zero
C. limit of resolution is decreased
D. limit of resolution is increased

Answer

B

Explanation

`I_(1) omega_(1) =I_(2)omega_(2)`
`Iomega_(1) =2Iomega_(2)`
`omega_(2) =(omega_(1))/(2) =(omega)/(2) `
New `KE =1/2 I omega^(2)`
`=1/2 2I ((omega)/(2))^(2) =(I omega^(2))/(4)`
Change in `Ke =1/2 Iomega ^(2) -(Iomega^(2))/(4) =(Iomega^(2))/(4 )`