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If M(z) = magnetisation of paramagnetic ...

If `M_(z)` = magnetisation of paramagnetic sample B= external magnetic field T= absolute temperature, C= curie constant then according to Curie's law in magnetism, the correct relation is

A

`M_(x) =(T)/(CB)`

B

`M_(z)=(CB)/(T)`

C

`C=(M_(z)B)/(T)`

D

`C=(T^(2))/(M_(z)B)`

Text Solution

Verified by Experts

The correct Answer is:
B

According to Currie's law,
`cancel lamdaprop 1/T` where `cancel lamda` - susceptibility
`therefoer cancel lamda =C/T` where C - curie's constant
`(M_(z))/(B) =C/Twhere cancel lamda=(M_(z))/(B)`
`therefore M _(z) =(BC)/(T)`
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