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The radius of the Na^(+) is 95 pm and th...

The radius of the `Na^(+)` is 95 pm and that of CI ion is 181 pm Predict the coordination number of `Na^(+)` ?

A

4

B

6

C

8

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(Na)+//r_(Cl).^(-)=95//181=0.52` which lies in the range
`=0.414-0.732`. Hence, C . N . Of `Na^(+)=6` .
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