In a metal oxide , the oxide ions are arranged in hexagonal close packing and metal lone occupy two - third of the octahedral voids .The formula of the oxide is

Options

A. MO
B. `M_(2)O_(3)`
C. `MO_(2)`
D. `M_(2)O`

Answer

B

Explanation

Suppose no. of `O^(2-)` ions = n
`:.` No .of octahedral voids = n
Metal ions (M) occupying octahedral voids `=(2)/(3)n`
`:.` Ratio of M : `O^(2-)=(2)/(3)n:n=(2)/(3):1=2:3`
i. e., formula is `M_(2) O_(3)`