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A solid AB has the NaCL structure, If ra...

A solid AB has the NaCL structure, If radius of cation `A^(+)` is 120 pm, calculate the maximum possible value of the radius of the anion `B^(-)`

A

240 pm

B

60 pm

C

`49.6` pm

D

290 pm

Text Solution

Verified by Experts

The correct Answer is:
D
For NaCl crystal,
Radius of cation / radius of anion `=0.414`
`(r_(A^(+)))/(r_(B^(-)))=0.414`
`r_(B^(-))=(r_(A^(+)))/(0.414)=(120)/(0.414)=290` pm
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