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The edge of unit of FC C Xe crystal is 6...

The edge of unit of `FC C Xe` crystal is 620 pm .The radius of Xe atom is

A

`189.37` pm

B

`209.87` pm

C

`219.25` pm

D

`235.16` pm

Text Solution

Verified by Experts

The correct Answer is:
C
`r=(a)/(2sqrt(2))=(620)/(2sqrt(2))=219.25` pm
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