An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centers of the faces of the cube .The empirical formula for this compound would be

Options

A. AB
B. `A_(2)B`
C. `AB_(3)`
D. `A_(3)B`

Answer

C

Explanation

A ions are at eight corners of the cube. Therefore
the no. of A ions in the unit cell `=(8)/(8)=1.` B ions are at the face centre of six faces. Therefore, its share in the unit cell `=(6)/(2)=3` . The formula is `AB_(3)` .