In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 "pm "` and `187` pm respectively .The crystal structure of this compound will be

Options

A. NaCl type
B. CsCl type
C. ZnS type
D. similar to diamond

Answer

B

Explanation

`r_(+)//r_(-)=(180)/(187)=0.962` which lies in the range of
`0.732-1.000`, hence co-ordination number = 8 i.e. the structure is CsCl type .