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The vapour pressuress of pure solvent an...

The vapour pressuress of pure solvent and solution are 120 mm and 108 mm respectively. The mole fraction of the solvent in the solution is

A

0.1

B

0.9

C

120/108

D

1.08

Text Solution

Verified by Experts

The correct Answer is:
B
According to Raout's
`(P_(1)^(0)-P)/p_(1)^(0)=X_(2)` (mole fraction of solute)
`(120-108)/120=X_(2)=0.1`
Mole fraction of solvent `=1-X_(2)=1-0.1=0.9`
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