n moles of a non volatile solute are dissolved in wg of water. If `K_(f)` is the molal depression constant of water, the freezing point of the solution will be

Options

A. `(1000 K_(f)W_(2))/W_(1)`
B. `(-1000 K_(f) n )/W_(1)`
C. `(1000 K_(f) W_(1))/n`
D. `(-1000K_(f) W_(1))/n`

Answer

B

Explanation

`Delta T_(f)=(1000 K_(f) W_(2))/(W_(1) xx M_(2))=(1000K_(f) n )/w`
`As T_(0) = 0 Hemce , T_(f) =- (1000K_(f) n)/W`