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dm^(3) of water contains 90 g of glucose...

`dm^(3)` of water contains 90 g of glucose. The mole fraction of glucose in the solution is

A

0.33

B

0.66

C

0.5/56.05

D

0.5/55.55

Text Solution

Verified by Experts

The correct Answer is:
C
`"Moles of water"="Mass"/"Molar mass"=1000/18=55.56`
Moles of glucose `="Mass"/"Molar mass"=90/180=0.5`
Mole fraction of glucose `= 0.5/(0.5 + 55.56)=0.5/56.06`
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