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4.9 g of H(2) SO(4) is present in 500 c...

4.9 g of `H_(2) SO_(4)` is present in ` 500 cm^(3)` of the solution has molarity.

A

0.2

B

0.1

C

0.01

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
B
`M= "Mass"/("Molar mass" xx V (dm^(3)))`=`4.9/(98 xx 5)=1/10=0.1`
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