What is the molarity of `H_(2)SO_(4)` solution that has a density 1.84 g/c c at `35^(@)`C and contains 98% by weight?

Options

A. 4.18 M
B. 8.14 M
C. 18.4 M
D. 18 M

Answer

C

Explanation

`98% H_(2)SO_(4)=98` g of `H_(2)SO_(4)` in 100 g of water
and `V=M/d :. W_(2)=98, V=(100g)/(1.84 g cm^(-3))`
`M=(W_(2) xx 100)/(M_(2) xx V(cm^(3)))=(98 xx 1000)/(98 xx 100/1.84)=1.84 xx 10 = 18.4`