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Mole fraction of C(3)H(5)(OH)(3) in a so...

Mole fraction of `C_(3)H_(5)(OH)_(3)` in a solution of 36 g of water and 46 g of glycerine is :

A

0.2

B

0.8

C

0.46

D

0.36

Text Solution

Verified by Experts

The correct Answer is:
A
No. of moles of water `=36/18 = 2`
No. of moles of glycerine `= 46/92 = 0.5
` :. "Mole fraction of glycerine" = 0.5/(0.5 + 2)=0.5/2.5=0.2`
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