How many grams of methanol would have to be added to water to prepare 150mL of solution which is `2M CH_(3)OH`?

Options

A. 9.6
B. 2.4
C. `9.6 xx 10^(3)`
D. `4.3 xx 10^(2)`

Answer

A

Explanation

`M = (W_(2) xx 1000)/(M_(2) xx V (cm^(3))) :. W_(2)=(M xx M_(2) xx V(cm^(3)))/1000`
`W_(2) = (2 xx 32 xx 150)/1000 = 9600/1000 = 9.6 g `