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The mole fraction of oxalic acid (Molar ...

The mole fraction of oxalic acid (Molar mass 63) required to prepare 0.10 m solution in water is

A

1

B

0.0018

C

6.3

D

0.0992

Text Solution

Verified by Experts

The correct Answer is:
B
`X_(2)= (mM_(1))/(1000+mM_(1))`
`=(0.1 xx 18)/(1000 + 0.1 xx 18)`
=0.0018
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