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120g of urea is present in 5L of solutio...

120g of urea is present in 5L of solution, the active mass of urea is

A

0.2

B

0.06

C

0.4

D

0.88

Text Solution

Verified by Experts

The correct Answer is:
C
Active mass = concentration = M
` :. M=W_(2)/(M_(2) xx V (L))=120/(60 xx 5)=12/30=0.4`
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