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6g of urea is dissolved in 90g of water....

6g of urea is dissolved in 90g of water. The relative lowering of vapour pressure is equal to

A

0.0196

B

0.5

C

0.1

D

0.0202

Text Solution

Verified by Experts

The correct Answer is:
A
`(P_(1)^(o)-P)/P_(1)^(o)=("Mass of solute/molar mass")/("Mass of soute"/"Molar mass"+"Mass of solvent"/"Molar Mass")`
`(6//60)/(6/60+90/18)=(1//10)/(1/10+5/1)=1/51=0.0196`
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