The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should be

Options

A. _273.04 K
B. 374.04 K
C. 37.404 K
D. 273 K

Answer

B

Explanation

`Delta T_(f) = i xx K_(b) xx m = 2 xx 0.52 xx 1 = 1.04`
` :. T_(f) = 100 + 1.04 =101.04^(@) + 273 =374.04 K`