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Elevation in boiling point was 0.52^(@)C...

Elevation in boiling point was `0.52^(@)C` when 6 g of a compound X was dissolved in 100 g of water. Molecular weight of X is (`K_(b)` of water is `5.2^(@)C` per 100 g of water)

A

120

B

60

C

180

D

342

Text Solution

Verified by Experts

The correct Answer is:
B

`M_(2) = (K_(b) xx W_(2))/(Delta T_(b) xx W_(1)) xx 1000 = (5.2 xx 6 xx 10 ^(-3))/(0.52 xx 100 xx 10^(-3))=60`
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