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Pure benzene freezes at 5.45^(@)C at a c...

Pure benzene freezes at `5.45^(@)C` at a certain place but a 0.374m solution of tetrachloroethane in benzene freezes at `3.55^(@)C`. The `K_(f)` for benzene is

A

5.08 K kg `"mol"^(-1)`

B

508 K kg `"mol"^(-1)`

C

0.508 K kg `"mol"^(-1)`

D

`50.8^(@) C `kg `"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(f) = Delta T_(f) // m = (5.45 - 3.55) // 0.374`
`= 5.08 K kg "mol"^(-1)`
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