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The freezing point of a 0.05 molal solut...

The freezing point of a `0.05` molal solution of a non-electrolyte in water is:
(`K_(f) = 1.86 "molality"^(-1)`)

A

`-1.86^(@)C`

B

`-0.93^(@) C`

C

`-0.093^(@)C`

D

`0.093^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta T_(f)= 1.86 xx 0.05 = 0.093 (Delta T_(f) = K_(f) xx m)`
`:. T_(f) = 0 - 0.093 = -0.093^(@)C`
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