Molal depression of freezing point of water is `1.86^(@)` per 100 g of water. 0.02 mole of urea dissolved in 100 g of water will produce a lowering of temperature of :

Options

A. `0.186^(@)`
B. `0.372^(@)`
C. `1.86^(@)`
D. `3.72^(@)`

Answer

B

Explanation

`Delta T_(f) = (1000 xx K_(f) xx n)/W_("solvent)=(1000 xx 1.86 xx 0.02)/100=0.372^(@)`