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A solution of 1.25g of a certain non-vol...

A solution of 1.25g of a certain non-volatile substance in 20g of water freezes at 271.94K. Calculate the molecular mass of the solute `(K_(f)=1.86" K kg mol"^(-1))`.

A

`179.97 g "mol"^(-1)`

B

`207.8 g "mol"^(-1)`

C

`209.6 g "mol"^(-1)`

D

`109.6 g "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`M_(2) = (K_(f) W_(2) xx 1000)/(Delta T_(f) W_(1))=(1.86 xx 1.25 xx 1000)/((273-271.94) xx20)=109.6`
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