Osmotic pressure of `40%` (wt.`//`vol.) urea solution is `1.64 atm` and that of `3.42%` (wt.`//`vol.) cane sugar is `2.46 atm`. When equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is:

Options

A. 1.64 atm
B. 2.46 atm
C. 4.10 atm
D. 2.05 atm

Answer

D

Explanation

`pi = (pi + pi_(2))/2=(1.64 + 2.46)/2 = 4.10/2=2.05 "atm"`
if equal volume are mixed, then volume of solution become double.