Following solutions at the same temperature will be isotonic

Options

A. 3.42 g of cane sugar in one litre water and 0.18 g of glucose in one litre water
B. 3.42 g of cane sugar in one litre water and 0.18 g of glucose in 0.1 litre water
C. 3.42 g of cane sugar in one litre water and 1.17 g of NaCl in one litre water
D. 3.42 g of cane sugar in one litre water and 1.17 g of NaCI in one litre water

Answer

B

Explanation

For isotonic solution, `pi_(1) = pi_(2)`
(and for nonelectrolytes also `C_(1) = C_(2))`
`pi_(1) = W/(M xx V) xx RT = 3.42 /(342 xx 1)RT = 0.01 RT`
`pi_(2) = 0.18/(180 xx 0.1) RT = 0.01 RT`