A solution containing 500 g of a protein per liter is isotonic with a solution containing 3.42 g sucrose per liter. The molecular mass of protein in 5 x `10^(x)`, hence x is.

Options

A. 5
B. 146
C. 34200
D. 50000

Answer

D

Explanation

For two non-electrolytic solution to be isotonic, `C_(1) = C_(2)`
`W_(1)/(M_(1) V_(1))=W_(2)/(M_(2) V_(2)) :. 500/ (M_(1) xx 1 ) = 3.42/(342 xx 1)`
`:. M_(1) = (500 xx 342)/3.42 = 50000.`