A solution of protein (extracted from carbs) was prepared by dissolving `0.75 g` in `125 cm^(3)` of an aqueous solution. At `4^(@)C` and osmotic pressure rise of `2.6 mm` of the solution was observed. Then molecular weight of protein is (assume density of solution is `1.00 g//cm^(3)`):

Options

A. `9.4 xx 10^(5)`
B. `5.4 xx 10^(5)`
C. `5.4 xx 10^(10)`
D. `9.4 xx 10^(10)`

Answer

B

Explanation

Given h = 2.6 mm
`pi = hdg = 2.6/10 xx 1 xx 980 "dyne" "cm"^(-2)`
Also `pi = W/(V.M) RT`
`(2.6 xx 1 xx 980)/10=(0.75 xx 8.314 xx 10^(7) xx 277)/(125 xx M)`
` :. M=5.4 xx 10^(5) g `