The solute 'A' is a ternary electrolyte and solute 'B' is a non- electrolyte. If 0.1 M solution of solute 'B' produces an osmotic pressure of 2P, then, 0.05 M solution of A at the same temperature will produce an osmotic pressure equal to

Options

A. 1.5 P
B. `2 P`
C. `3 P`
D. P

Answer

C

Explanation

0.05 M solution of `A = 3 xx 0.05` M ion (Ternary, i=3)
`=0.15 M "ions."` 0.1 M solution of B (non-electrolyte) has osmotic pressure `= 2 P = pi_(2)`
:. 0.15 M solution will have osmotic pressure = `pi_(1)` As `pi_(1)C_(2) = pi_(2) C_(1)`
`:. pi_(1) = (pi_(2)C_(1))/C_(2)=(2P xx 0.15 M )/(0.1 M )=(2P)/0.1 xx 0.15 = 3P`