The `BaCl_(2)` ionises to an extent of 80% in aqueous solution, the value of van't Hoff factor is -

Options

A. 2.6
B. 0.4
C. 0.8
D. 2.4

Answer

A

Explanation

`BaCl_(2) rarr Ba^(2+) + 2Cl^(-) :. n=3`
`alpha = (% alpha)/100 =80/100=0.8`
`alpha = (i-1)/(n-1)`
`:. 0.8 = (i-1)/(3-1)`
` :. 0.8 xx 2 = i - 1`
1.6 + 1 = I
i=2.6`