The freezing point (in `.^(@)C)` of a solution containing `0.1 g` of `K_(3)[Fe(CN)_(6)]` (Mol.wt. 329) in 100 g of water `(K_(f) = 1.86 K kg mol^(-1))` is

Options

A. `-2.3 xx 10^(-2)`
B. `-5.7 xx 10^(-2)`
C. `-5.7 xx 10^(-3)`
D. `-1.2 xx 10^(-2)`

Answer

A

Explanation

`K_(3)[Fe (CN)_(6)] rarr 3K^(+) + [Fe (CN)_(6)]^(3-)`
:. i=4
`Delta T_(f) = iK_(f) m = i xx K_(f) xx W_(2)/M_(2) xx 1/W_(1) xx 1000`
`= 4 xx 1.86 xx 0.1 /329 xx 1/100 xx 1000`
`=0.023 = 2.3 xx 10^(-2) .^(@)C or K`
`:. T_(f) = 0 - 2.3 xx 10^(-2) .^(@)C = -2.3 xx 10^(-2) .^(@)C`