In the reaction: `3Br_(2)+6OH^(Theta)rarr 5Br^(Theta)+BrO_(3)^(Theta)+3H_(2)O,Br_(2)` is

Options

A. is reduced
B. is oxidized
C. disproportionates
D. disintegrate

Answer

C

Explanation

`3Br_(2)+6OH^(-) to overset((-1))(5Br^(-))+overset((+5))(BrO_(3)^(-))+3H_(2)O`
In this reaction, O.S of bromine changes from (i) 0 to -1, and (ii) 0 to +5. Hence, `Br_(2)` is reduced to `Br^(-)` and also oxidized to `BrO_(3)^(-)`. Thus, `BrO_(3)^(-)` is oxidized as well as reduced. In other words, undergoes disproportionation.