In which of the following compounds, the oxidation stable of xenon is not six ?

Options

A. `XeF_(2)`
B. `XeOF_(4)`
C. `XeOF_(2)`
D. `XeO_(3)`

Answer

To determine which of the given compounds has an oxidation state of xenon that is not six, we will analyze the oxidation states of xenon in each compound step by step.

### Step 1: Analyze the first compound, XeF2
- **Formula:** XeF2
- **Oxidation state calculation:**
- Let the oxidation state of xenon (Xe) be \( x \).
- Each fluorine (F) has an oxidation state of -1.
- The compound is neutral, so we set up the equation:
\[ x + 2(-1) = 0 \]
\[ x - 2 = 0 \implies x = +2 \]
- **Conclusion:** The oxidation state of xenon in XeF2 is +2.

### Step 2: Analyze the second compound, XeF4
- **Formula:** XeF4
- **Oxidation state calculation:**
- Let the oxidation state of xenon (Xe) be \( x \).
- Each fluorine (F) has an oxidation state of -1.
- The compound is neutral, so we set up the equation:
\[ x + 4(-1) = 0 \]
\[ x - 4 = 0 \implies x = +4 \]
- **Conclusion:** The oxidation state of xenon in XeF4 is +4.

### Step 3: Analyze the third compound, XeO3
- **Formula:** XeO3
- **Oxidation state calculation:**
- Let the oxidation state of xenon (Xe) be \( x \).
- Each oxygen (O) has an oxidation state of -2.
- The compound is neutral, so we set up the equation:
\[ x + 3(-2) = 0 \]
\[ x - 6 = 0 \implies x = +6 \]
- **Conclusion:** The oxidation state of xenon in XeO3 is +6.

### Final Analysis:
- From our calculations:
- In XeF2, the oxidation state of xenon is +2.
- In XeF4, the oxidation state of xenon is +4.
- In XeO3, the oxidation state of xenon is +6.

### Answer:
The compounds where the oxidation state of xenon is not +6 are **XeF2** and **XeF4**.