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CH(3)CH(2)underset(Br)underset(|)(CH)CH(...

`CH_(3)CH_(2)underset(Br)underset(|)(CH)CH_(2)CH=CH_(2) overset("alcoholic KOH")rarr A` (predominant) A is

A

`CH_(3)CH_(2)CH=CHCH=CH_(2)`

B

`CH_(3)CH_(2)=CHCH_(2)CH=CH_(2)`

C

`CH_(2)=CHCH_(2)CH_(2)CH=CH_(2)`

D

`CH_(2)CH_(2)CH_(2)CH_(2)C-=CH`

Text Solution

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The correct Answer is:
A
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