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CH3underset(CH3)underset(|)oversetoverse...

`CH_3underset(CH_3)underset(|)oversetoverset(CH_3)|C-undersetunderset(OH)|CHCH_3 overset(HBr)to A ` (predominant), A is

A

`(CH_3)_3C oversetoverset(Br)|CHCH_3`

B

`(CH_3)_2oversetoverset(Br)|C CH(CH_3)_2`

C

both 'a' and 'b'

D

none is correct

Text Solution

Verified by Experts

The correct Answer is:
B
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