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Calculate the work done during compress...

Calculate the work done during compression of 2 mol of an ideal gas from a volume of `1m^(3)` to `10 dm^(3)` 300 K against a pressure of 100 KPa .

A

99 kJ

B

`-99` kJ

C

`114.9` kJ

D

`-114.9` kJ

Text Solution

Verified by Experts

The correct Answer is:
A
n=2 moles, `V_(1) = 1m^(3) = 10^(3)dm^(3), V_(2) = 10 dm^(3), P_(ex) = 100 kPa`
For isothermal Irreversible process
`W = -Pex (V_(2)-V_(1))`
`=-100 kPa (10 dm^(3) -1000 dm^(3))`
`=-100 (-900) kPa xx dm^(3) = 99000 J`
= 99 kJ
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