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In the cell represented by Pb(s) |Pb^(...

In the cell represented by
`Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s)`
the reducing agents is

A

Pb

B

`Pb^(2+)`

C

Ag

D

`Ag^(+)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Pb(s)| Pb^(2+) (1M) ||Ag^(+)(1M)| Ag_(s)`
The compound losing `e^(-)` is called reducing agent.
`Pb to Pb^(2+) + 2e^(-)`
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