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The reaction takes place in two ste...

The reaction takes place in two steps as
`(i) NO_(2) Cl _((g)) overset(K_(1)) to NO_(2(g)) +Cl_((g))`
`(ii ) NO_(2) Cl_((g)) +Cl_((g)) overset(K_(2)) to NO_(2(g)) +Cl_(2(g))`
Identify the reaction intermediate .

A

`NO_(2)Cl`(g)

B

`NO_(2)`(g)

C

`Cl_(2)(g)`

D

Cl(g)

Text Solution

Verified by Experts

The correct Answer is:
D
`NO_(2)Cl(g) overset(K_(1))to NO_(2)(g) + Cl_(g)`(free radical)
`NO_(2)Cl(g) + Cl(g) overset(K_(2))to NO_(2)(g) + Cl_(2)(g)` (The intermediate generated is Cl)
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