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function f and g are defined as follows: `f:RR-{1} rarr RR,` where `f(x) =(x^(2)-1)/(x-1)` and `g: RR rarr RR g(x)=x+1, RR` being the set of real numbers .Is `f=g`? Give reasons for your answer.

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The correct Answer is:
`f ne ` domain of g. Therefore , `f ne g`
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