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Let A ={x:-1 le x le 1} and f: A rarr A ...

Let `A ={x:-1 le x le 1} and f: A rarr A` be defined by `f(x) ="sin" (pix)/(2) ` . Show that f is a one- one onto mapping and hence find a formula that defines `f^(-1)`

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The correct Answer is:
`=(2)/(pi) sin ^(-1) x`
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