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CHHAYA PUBLICATION-TRIGONOMETRIC INVERSE CIRCULAR FUNCTIONS-Short answer type questions
- 4 ( tan ^(-1) ""(1)/(3) + cos ^(-1)""(2)/(sqrt(5)))=pi
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- tan^(-1)""(1)/(2) +tan ^(-1) ""(2)/(11 ) = cos^(-1) ""(4)/(5)
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- sin ^(-1)""(77)/(85) -cos^(-1)""(15)/(17)= sin ^(-1) ""(3)/(5)
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- 2 ( tan ^(-1)""(1)/(4) +tan ^(-1)""(2)/(9))=cos ^(-1)""(3)/(5)
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- 2 tan ^(-1)""(1)/(3) + sin ^(-1)""(4)/(5) =(pi)/(2)
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- cos^(-1)""(2)/(sqrt(5))+sin ^(-1)""(1)/(sqrt(10))=(pi)/(4)
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- 2sin ^(-1)""(3)/(5) +sin ^(-1) ""(7)/(25)=(pi)/(2)
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- tan ^(-1) ""(1)/(3) + tan^(-1)""(1)/(7)+tan ^(-1)""(1)/(5)+tan ^(-1)...
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- tan ^(-1)x+cot^(-1)(x+1) = tan ^(-1) (1+x+x^(2))
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- tan ^(-1)""(1)/(p+q)+tan ^(-1)""(q)/(p^(2)+pq+1)=cot^(-1)p
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- tan^(-1)""(3)/(2) +tan^(-1)""(6)/(5)=pi - tan^(-1)""(27)/(8)
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- tan((1)/(2) sin ^(-1)""(2x)/(1+x^(2))+(1)/(2)cos^(-1)((1-x^(2))/(1+x^(...
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- tan ^(-1)x-tan ^(-1)y=sin ^(-1) ""(x-y)/(sqrt((1+x^(2))(1+y^(2)))
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- sin^(-1)x+sin^(-1)y=cos^(-1)""{sqrt((1-x^(2))(1-y^(2)))-xy}
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- sin^(-1) ""(2a)/(1+a^(2))-cos^(-1) ""(1-b^(2))/(1+b^(2))=2tan ^(-1) ""...
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- cot^(-1)""(xy+1)/(x-y)+cot^(-1)""(yz+1)/(y-z) +cot ^(-1) "" (zx +1)/(...
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- tan^(-1)""(x-y)/(1+xy)+tan^(-1)""(y-z)/(1+yz)+tan^(-1)""(z-x)/(1+zx) =...
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- cos^(-1)x= 2 sin ^(-1) sqrt((1-x)/(2))=2 cos ^(-1)""sqrt((1+x)/(2))=2t...
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- { cos (sin ^(-1) x)}^(2) ={sin (cos ^(-1) x)}^(2)
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- tan ^(1)(cotx) + cot ^(-1) (tan x)=pi -2x
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