Home
Class 12
MATHS
The system of equation x+y+2z=1, x+2y+...

The system of equation`
` `x+y+2z=1, x+2y+3z=2, x+4y+alphaz=4`. Has unique then

A

`alpha !=3`

B

`alpha!=5`

C

`alpha!=2`

D

`alpha!=1`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ADJOINT AND INVERSE OF A MATRIX AND SOLUTION OF LINEAR SIMULTANEOUS EQUATIONS BY MATRIX METHOD

    CHHAYA PUBLICATION|Exercise MATRIX MATCH TYPE|2 Videos
  • ADJOINT AND INVERSE OF A MATRIX AND SOLUTION OF LINEAR SIMULTANEOUS EQUATIONS BY MATRIX METHOD

    CHHAYA PUBLICATION|Exercise COMPERHENSION TYPE|6 Videos
  • ADJOINT AND INVERSE OF A MATRIX AND SOLUTION OF LINEAR SIMULTANEOUS EQUATIONS BY MATRIX METHOD

    CHHAYA PUBLICATION|Exercise MULTIPLE CORRECT ANSWER TYPE|5 Videos
  • ALGEBRA

    CHHAYA PUBLICATION|Exercise JEE ADVANCED ARCHIVE 2016|5 Videos

Similar Questions

Explore conceptually related problems

If the system of equations x+y+z = 5 x + 2y + 3z = 9 x + 3y + alphaz = beta has infinitely many solution, then beta - alpha equals

The system of equation x+y+z=6, x+4y+6z=20, x+4y+mz=n . Has no solution then

If the system of equations x+2y+3z=1, 2x+ky+5z=1, 3x+4y+7z=1 has no solutions, then -

Examine the consistency of the system of equations x+ y +z=1 2x+ 3y +2z =2 ax+ay +2az =4

If the system of equations x+y+z=6, x+2y+kz=0 and x+2y+3z=10 has no solution, then the value of k is -

For what values of p and q the system of equations 2x+py+6z=8, x+2y+qz=5, x+y+3z=4 has (i) no solution (ii) a unique solution (iii) in finitely many solutions.

The system of equations -2x+y+z=a , x-2y+z=b , x+y-2z=c , has: (a)no solution if a+b+c!=0 (b)unique solution if a+b+c=0 (c)infinite number of solutions if a+b+c=0 (d)none of these

The value of k for which the system of equations x+ky-3z=0 , 3x+ky-2z=0, 2x+3y-4z=0 has a non -trivial solution is

The values of k in R for which the system of equations x+k y+3z=0,k x+2y+2z=0,2x+3y+4z=0 admits of nontrivial solution is a. 2 b. 5//2 c. 3 d. 5//4