Home
Class 12
MATHS
The cartesian equation of a line is give...

The cartesian equation of a line is given by : `6x-1=3y+2=2x-2`. Find its direction ratios and reduce it to vector form.

Text Solution

Verified by Experts

The correct Answer is:
Where t is a real paramenter.
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINE IN THREE DIMENSINAL SPACE

    CHHAYA PUBLICATION|Exercise Exercise 4A|81 Videos

  • STRAIGHT LINE IN THREE DIMENSINAL SPACE

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination|19 Videos

  • SIGNIFICANCE OF DERIVATIVE AS RATE OF CHANGE

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITVE EXAMINATION|20 Videos

  • TANGENT AND NORMAL

    CHHAYA PUBLICATION|Exercise ASSERTION-REASON TYPE|2 Videos

Similar Questions

Explore conceptually related problems

The Cartesian equations of a line are 6x-2=3y+1=2z-2. Find its direction ratios and also find a vector equation of the line.

(i) Find the vector equation of a line passing through a point with position vector 2hat(i)-hat(j)+hat(k) , and parallel to the line joining the points -hat(i)+4hat(j)+hat(k) and hat(i)+2hat(j)+2hat(k) . Also find the cartesian equivalent of this equation. (ii) The cartesian equations of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find vector equation of the line.

The cartesian equations of a line are x= ay+b,z= cy+d . Find its direction ratios.

The cartesian equation of a line AB is (3-x)/1=(y+2)/-2=(z-5)/4 . Find the direction ratios of a line parallel to AB.

The cartesian equation of a line is (2x-5)/(3)=(6-3y)/(2)=(z+1)/(6) . Find the direction ratios of the given line.

The cartesian equation of a line is 3x+2=5y-4=3-z . Find a point on the line and its direction ratios, hence rewrite this equation in symmetric from and then reduce it to vector form.

The cartesian equation of a line AB is (3-x)/(1)=(y+2)/(-2)=(z-5)/(4) . Find the direction ratios of a line parallel to AB.

The Cartesian equation of a line is (x-3)/2=(y+1)/(-2)=(z-3)/5 . Find the vector equation of the line.

The equation of a line is given by x=by+c, z=ay+d , write it in cartesian form and vector form.

The cartesian equations of a line are 3x+1=6y-2=1-z . Find the fxed point through which it passes, its direction ratios and also its vector equation.

CHHAYA PUBLICATION-STRAIGHT LINE IN THREE DIMENSINAL SPACE -Sample Questions for Competitive Examination
  1. The cartesian equation of a line is given by : 6x-1=3y+2=2x-2. Find it...

    Text Solution

    |

  2. The symmetrical from of the lines x+y+z-1=0 and 4x+y-2z+2=0 are -

    Text Solution

    |

  3. The equation of line passing through the point vec(a) parallel to the ...

    Text Solution

    |

  4. The lines vec(r)=hat(i)+hat(j)-hat(k)+lamda(3hat(i)-hat(j)) and vec(r)...

    Text Solution

    |

  5. Consider the lines (x-5)/(3)=(y-7)/(-16)=(z-3)/(7) and (x-9)/(3)=(y-13...

    Text Solution

    |

  6. The distance of the point A(veca) from the line vec(r)=vec(b)+tvec(c)...

    Text Solution

    |

  7. If the length of the perpendicular drawn from (1,2,3) to the line (x-6...

    Text Solution

    |

  8. If the shortest distance between the lines (x-1)/(1)=(y-1)/(1)=(z-1)/(...

    Text Solution

    |

  9. The line (x-2)/(3)=(y+1)/(2)=(z-1)/(-1) intersects the curve xy xy=c^(...

    Text Solution

    |

  10. A line passing through the point (1,1,1) from a tiangle of area sqrt(6...

    Text Solution

    |

  11. The direction cosines of two lines satisfy the relations lamda(l+m)=n ...

    Text Solution

    |

  12. Each question in this section contains statements given in two columns...

    Text Solution

    |

  13. vec(a)=6hat(i)+7hat(j)+7hat(k),vec(b)=3hat(i)+2hat(j)-2hat(k),P(1,2,3)...

    Text Solution

    |

  14. vec(a)=6hat(i)+7hat(j)+7hat(k),vec(b)=3hat(i)+2hat(j)-2hat(k),P(1,2,3)...

    Text Solution

    |

  15. vec(a)=6hat(i)+7hat(j)+7hat(k),vec(b)=3hat(i)+2hat(j)-2hat(k),P(1,2,3)...

    Text Solution

    |

  16. L(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) ...

    Text Solution

    |

  17. L(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) ...

    Text Solution

    |

  18. L(1):(x+1)/(-3)=(y-3)/(2)=(z+2)/(1),L(2):(x)/(1)=(y-7)/(-3)=(z+7)/(2) ...

    Text Solution

    |

  19. Statement - I: The point A (1,0,7) is the mirror image of the point B(...

    Text Solution

    |

  20. Statement - I : The lines vec(r)=hat(i)+hat(j)-hat(k)+S(3hat(i)-hat(j)...

    Text Solution

    |