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The shortest distance between the lines `vec(r)=vec(a)_(1)+tvec(b)_(1)` and `vec(r)=vec(a)_(2)+svec(b)_(2)` is -

A

`(|(vec(a)_(2)-veca_(1))*(vec(b_(1))xxvec(b)_(2))|)/(|vec(b)_(1)xxvec(b)_(2)|)`

B

`(|(vec(a)_(2)+veca_(1))*(vec(b_(1))xxvec(b)_(2))|)/(|vec(b)_(1)xxvec(b)_(2)|)`

C

`(|(vec(a)_(2)-veca_(1))*(vec(b_(1))xxvec(b)_(2))|)/(|vec(b)_(1)xxvec(b)_(2)|^(2))`

D

`(|(vec(a)_(2)+veca_(1))*(vec(b_(1))xxvec(b)_(2))|)/(|vec(b)_(1)xxvec(b)_(2)|^(2))`

Text Solution

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The correct Answer is:
A
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CHHAYA PUBLICATION-STRAIGHT LINE IN THREE DIMENSINAL SPACE -Exercise 4A
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