Find the angles of the triangle whose sides are `y+2=0,sqrt(3)x+y=1andy-sqrt(3)x+2+3sqrt(3)=0`
Text Solution
Verified by Experts
The correct Answer is:
`=180^(@)-(60^(@)+60^(@))=180^(@)-120^(@)=60^(@)`
Topper's Solved these Questions
STRAIGHT LINE
CHHAYA PUBLICATION|Exercise EXERCISE 2A (Multiple Choice Type Questions)|20 Videos
STRAIGHT LINE
CHHAYA PUBLICATION|Exercise EXERCISE 2A(Very Short Answer Type Questions)|14 Videos
MATHEMATICAL INDUCTION
CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams|20 Videos
Similar Questions
Explore conceptually related problems
sqrt(3)x^(2) - sqrt(2)x + 3sqrt(3)=0
Find the angles of the triangle whose sides are (sqrt(3)+1)/(2sqrt(2)), (sqrt(3)-1)/(2sqrt(2)) and sqrt(3)/2 .
Find the angle between the straight lines : y-(2+sqrt(3))x=6andy=(2-sqrt(3))x+9
tan^(2)x -(1+sqrt(3))tanx + sqrt(3)=0
Find the values of alpha such that the variable point (alpha, "tan" alpha) lies inside the triangle whose sides are y=x+sqrt(3)-(pi)/(3), x+y+(1)/(sqrt(3))+(pi)/(6) = 0 " and " x-(pi)/(2) = 0
Prove that the disgonals of the parallelogram whose sides are sqrt3x+y=0 , sqrt3y+x=0 ,'sqrt3x+y=1'and sqrt3y+x=1 are perpendicular to each other.
A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)
Find the angle between the two lines x-sqrt3y=3 and sqrt3x-y+1=0
Find the obtuse angle between the lines x-y+2=0 and (2-sqrt(3))x-y+1=0 .
Find the area of the closed figure bounded by the curves y=sqrt(x),y=sqrt(4-3x) and y=0
CHHAYA PUBLICATION-STRAIGHT LINE-Sample Questions for Competitive Exams (Assertion-Reason Type)